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Fig. 5. Fibril distribution after shear. (A) Summed confocal images of matrix stained with anti-FN antibodies taken in areas of shear corresponding to 0 and 250 dynes/cm2. Note the hole (outlined in red) in the matrix spun at 250 dynes/cm2. (B) Fluorescence intensities under the lines in panel A are plotted versus distance along the line, with red regions indicating areas threefold brighter than the average hole intensity. Assuming that fibril fluorescence intensity is additive, the average peak intensity of single fibrils, 62±15 a.u., was used to establish the scale to the right of the lower plot. Using this scale and the indicated peaks (open arrowheads), we calculated that lines from matrices exposed to 0 and 250 dynes/cm2 shear stress contained 65 and 49 fibrils, respectively. The cross-sectional area under the line was calculated by multiplying 10 µm matrix thickness by the distance along the line (x-axis in panel B, excluding the hole area for the 250 dynes/cm2 line). Fibril density was then calculated by dividing the total number of fibrils by the cross-sectional area, which gave similar fibril densities: 0.08±0.04/µm2 and 0.07±0.03/µm2 for 0 and 250 dynes/cm2, respectively.
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